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Solution manal of algebral

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Solution manal of algebral

44958Solutions for C hapter 2 Problems1Vectors in the Cartesian Coordinate SystemP2.1: Given P(4.2.1) and ApQ=2ax +4a, +6az. find the point Q.Apq = 2

Solution manal of algebral ax + 4 ay + 6 ax = (Qx-Px)«x + (Qy-Py)ay+(Qx-Px)axQx-Px=Qx 4=2; Qx=6Qy-Py=Qy-2=4; Qy=6QrP>Qrl=6; Q>7Ans: Q(6.6.7)P2.2: Given the points P(4,1.0)111 a

nd Q( 1.3.0)111. fill in the table and make a sketch of the vectors found in (a) though (f).__________________________________________________________ Solution manal of algebral

____VectorMagUnit Vectora. Find the vector A from the origin to pAop = 4 ax + 1 ay4 12Aop = 0.97 ax + 0.24 ayb. Find the vector B from the origin to Ọ

Solution manal of algebral

Boq = 1 ax + 3 ay3.16aoQ = 0.32 ax + 0.95 ayc. Find the vector C from p to QCpQ = -3 ax + 2 ay3.61aPQ = -0.83 ax + 0.55 ayd Find A - BA + B = 5 ax + 4

44958Solutions for C hapter 2 Problems1Vectors in the Cartesian Coordinate SystemP2.1: Given P(4.2.1) and ApQ=2ax +4a, +6az. find the point Q.Apq = 2

Solution manal of algebral = (4-0)ax + (l-0)ay + (0-0)ax = 4 ax + 1 ay. |Aop| = V42 + 1- = 717=4.12ao? = -j=a. +—7=a_ = 0.97a. + 0.24a,.717 VĨ7 y(see Figure P2 2ab)b.BC<| =(l-0

)ax + (3-0)ay + (0-0)a2 = 1 ax + 3 a,..|B^| = Vl:+3; = 710 = 3.16aoo = —?= a. +—5= a, = 0.32a. + 0.95a,.; 710 7ĨÕ y x y(see Figure P2 2ab)c.CpQ = (l-4 Solution manal of algebral

)ax + (3-1 )ay + (0-0)az = -3 ax + 2 ay.|c^| = s/3:+2; = 713 =3.61-32apo = —1-7 a + -C—av = -O.83ax + 0.55a,.713713 y(see Figure P2 2cd)44959d.A + B =

Solution manal of algebral

(4+1 )ax + (l+3)ay + (0-0)az = 5 ax + 4 ay.|A + B = ự.<+4- = 741 =6.454a - -7=at + —7—a, = 0.78a, + 0.62a,

44958Solutions for C hapter 2 Problems1Vectors in the Cartesian Coordinate SystemP2.1: Given P(4.2.1) and ApQ=2ax +4a, +6az. find the point Q.Apq = 2

44958Solutions for C hapter 2 Problems1Vectors in the Cartesian Coordinate SystemP2.1: Given P(4.2.1) and ApQ=2ax +4a, +6az. find the point Q.Apq = 2

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