Solution of Optics-Modern-Physics-2E-Sol--DC-Pandey

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Solution of Optics-Modern-Physics-2E-Sol--DC-Pandey

Solutions ofOptics &Modern PhysicsLesson 26th to 30thBy DC Pandey26. Reflection of LightIntroductory Exercise 26.11.Since c = —J—— where c is the spee

Solution of Optics-Modern-Physics-2E-Sol--DC-Pandey ed of lightvMo£oin vacuum hence unit of .. is m/s.2.HenceBy = 2x10 7 Tsin|500x + 1.5x 10**d Comparing this equation with the standard wave eqution By

= Bụ sin l&x + cod*=500m l=>k=~k, 2ji____ir=>k = —m = -T~ metre500250(0=1.5x IO11 rad/s=>2 Jtn = 1.5x10"=>n=^xl0nHz2nQ___J ...________(O 1.5 X 101’Spe Solution of Optics-Modern-Physics-2E-Sol--DC-Pandey

ed of the wave V = — - ——--k 500= 3 X 10* m/sLetE() be the amplitude of electric field.Then Et) = cBq 3 X 10- X 2 X 10 7= 60V/mSince wave is propagati

Solution of Optics-Modern-Physics-2E-Sol--DC-Pandey

ng along X-axis and B along .y-axis, hence E must be along 2-axis => E =60V/m sin 1500x + 1.5 X 10ndIntroductory Exercise 26.21. Total deviation produ

Solutions ofOptics &Modern PhysicsLesson 26th to 30thBy DC Pandey26. Reflection of LightIntroductory Exercise 26.11.Since c = —J—— where c is the spee