Griffith introduction to quantum mechanics

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Griffith introduction to quantum mechanics

https: //k hot h u vien .comSolution Manual to Introduction to Quantum Mechanics byD Griffith Plus correctionsww.elsQluciQnariQ.netErrataInstructor’s

Griffith introduction to quantum mechanics Solutions Manual Introduction to Quantum Mechanics Author: David Griffiths Date: June 14, 2001Page 3, Prob. 1.6(b): last two lines should read=+= a2+

2X-Page 8, Prob. 2.6(b): in the first box, the argument of the sscond sine should include an X.Page 9, Prob. 2.9: in tbe last line, Cl = 8VĨ5/X3.Page Griffith introduction to quantum mechanics

10, Prob. 2.11: in the third line the proof assumes that g (which in our case will be a_ V') docs not actually blow up at ±oo faster than / (in our ca

Griffith introduction to quantum mechanics

se VO goes to zero. I don’t know how to fix this defect without appealing to the analytic approach, where we find (Eq. 2.60) that t!>(r) goes asymptot

https: //k hot h u vien .comSolution Manual to Introduction to Quantum Mechanics byD Griffith Plus correctionsww.elsQluciQnariQ.netErrataInstructor’s

Griffith introduction to quantum mechanics 1997), the expression for c at the end of (a) should indude a factor of i. Also, add at the end of (a): “(The signs arc conventional.)" In part (b).

every s/fej should carry a factor of t (i.e. insert»three times in the first line, i" three times in the next line, and (—»■)" in the boxed answer).Pa Griffith introduction to quantum mechanics

ge 11, Prob. 2.14(a): for the same reason, in the third line, remove the t in the expression for Ộ1-Page 19, Prob. 2.30: or •... tanz «z ■ ự(zo/x)a -

Griffith introduction to quantum mechanics

1 = (l/z)y6£ - z1. Now (Eqs. 2.130 and 2.137) zg - za = sV, so z5 = Ka. But zẵ - Xs = z4 « 1 X w 2

https: //k hot h u vien .comSolution Manual to Introduction to Quantum Mechanics byD Griffith Plus correctionsww.elsQluciQnariQ.netErrataInstructor’s

Griffith introduction to quantum mechanics ion value of X in the nth stationary slate. 'Ihe remaining integral is; £x" (?) •*" c?) “«£1 [“*£?)■ “• c?)] *-(ỈM*?)]!;-*Evidently, then,«-ẳ(í)^(ỉ)-[

SPage 23, Prob. 2.37: Because of the i and -i inserted In Eqs. 2.52 and 2.53 respectively (see Corrections ^2—June 1997), line 3 on should read as fol Griffith introduction to quantum mechanics

lows:<*) ~ JjTrn. Ị ~a-^ndx-BmH** "[2.52)1Í a-Vs. - -iựnÃũnfc._i [2.53) J’(*) =ị Vi"+!)*«» Ị iQỶn+idx+y/nĩĩù Ị=[o)(by the orthogonality of {tf„}). Als

Griffith introduction to quantum mechanics

o (p) »*=[Õ7Ị Meanwhilealf’ “" a_)(a+ “ °”) = 2^(o’ - a+<*~ “ °-a+ + a-)180“ 2ii Ị^"^°+ “ a+a~ “ a"a+ +o-^" Bulaịýn =

https: //k hot h u vien .comSolution Manual to Introduction to Quantum Mechanics byD Griffith Plus correctionsww.elsQluciQnariQ.netErrataInstructor’s