Solution manual ch02 of algebra

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Solution manual ch02 of algebra

Section 2.1Chapter 2Check Point Exercises14(2x + l) = 29 + 3(2x-5)8x + 4 = 29 + 6x-15 8x + 4 = 14 + 6x 8x-6x = 14-42x = 102x = 10x = 5 Check:4(2x + l)

Solution manual ch02 of algebra) = 29 + 3(2x-5) 4(2(5)+ 1] = 29+ 3(2(5)-5] 4(10 + 1) = 29+ 3(10-5]4(11] = 29+ 3(5] 44 = 29 + 157x-2l = 10-4X-20 7x-21 = —lx-10 7x + 4x = -10 + 21 1lx

= 11 lie u 11 " 11 X = 1Check: x-3 5 x + 5 4 "1471-3 5 1 + 5 4 "147-2 =_5__6 4 "14 72" 2The solution set is {1}.0.517118 T—= 18r.il-18x.-L2x183x45 = Solution manual ch02 of algebra

17x-645 + 6 = 17x-6 + 651 = 17x51 = 17x17173 = XThe solution set is {3}.X 224=XX 2x-2 x-2 33(x-2)—= 3(x-2) -^--7 x-2L*-2 3.3(* - 2)'——- = (3x - 2) ■ -

Solution manual ch02 of algebra

Ị-- 3(x - 2) ■ IX - 2X - 233x=6-(x-2)-2 3x = 6-2(x-2) 3x = 6-2x + 4 3x = 10-2x3x + 2x = 10-2x + 2x5x = 105x_105 ■ 5 X = 2The solution set is the empty

Section 2.1Chapter 2Check Point Exercises14(2x + l) = 29 + 3(2x-5)8x + 4 = 29 + 6x-15 8x + 4 = 14 + 6x 8x-6x = 14-42x = 102x = 10x = 5 Check:4(2x + l)