Schaum’s outline of theory and problems (6)
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Schaum’s outline of theory and problems (6)
ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) -1■-3a, “3a,-6a,14 COORDINATE SYSTEMSA problem which has cylindrical or spherical symmetry could be expressed and solved in the familiar cartesian coordinate system. However, the solution would fail to show the symmetry and in most cases would be needlessly complex, 'l"hercforc, throughout this book Schaum’s outline of theory and problems (6) , in addition to the cartesian coordinate system, the circular cylindrical and the spherical coordinate systems will be need All three will he examineSchaum’s outline of theory and problems (6)
d together in order to illustrate the similarities and the differencesA point p is described by three coordinates, in cartesian (x, y, z), in circularELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) y followed. The angle Ộ is the same angle in both the cylindrical and spherical systems. But, in the order of the coordinates, Ộ appears in the second position in cylindrical, (r,Schaum’s outline of theory and problems (6)
for two quite different things In cylindrical coordinates r measures Che distance from the z axis in a plane normal to the z axis, while in the spheriSchaum’s outline of theory and problems (6)
cal system r measures the distance from the origin to the point. It should be dear from the context of the problem which r ic intendedA point is also ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) t., y-const., and z« const. In cylindrical coordinates, z -const, is the same infinite plane ax in cartesian; ự> -const, is a half plane with its edge along the z axis; r - const, is a right circular cylinder. These three surfaces are orthogonal and their intersection locales point p. In spherical c Schaum’s outline of theory and problems (6) oordinates, Ộ ■ const, is the same half plane as in cylindrical; r —const. is a sphere with its center at the origin; Ơ-const, is a right circular conSchaum’s outline of theory and problems (6)
e whose axis IS the z axis and whose vertex is at the origin. Note that 0 is limited to the range Os Ỡ Sx,figure 1-4 slivwa the three unit »cdvn at pvELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) (except in the case of af). Each unit vector is normal to its coordinate surface and is in the direction in which the coordinate increases. Notice that all these systems are right-handed:•, X Ba = ■»CHAP. 6|CURRENT, CURRENT DENSITY. AND CONDUCTOR.6.43.In cylindrical coordinates. J ■ lOr (A/m2) (or ( Schaum’s outline of theory and problems (6) he region 0.01 Sr < 0.02 m. 0Schaum’s outline of theory and problems (6)
en a current densityJ-(A/m*)in spherical i-wtdinalcs. find the current crossing the cvntcol strip Ỡ - rt/4. 0.001 = r = 0.080III. Ans. 1.38x10* A6.44.ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) y \ + 2xya, (A/m*). Am. 3.0 A6.46.As shown tn Fig. 6-IV, a current of 50 A passes down the I axis, enters a thin spherical shell ot radius 0.03m. and at 8 = jr/2 enters a plane sheet. Write expression* for the current sheet densities K in the spherical shell and in the plane.JSuL2657 96Ans. (A A"). Schaum’s outline of theory and problems (6) (A/nt)sin ifr6.47.A filamentary current of /(A) passes down the I axis to z■ 5X 10 ’in where it enters the portion OíộSx/4 of a spherical shell of radSchaum’s outline of theory and problems (6)
ius 5 X 10 *111. Find K for this current sheet.80/*" ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 - Schaum’s outline of theory and problems (6) ne, (b) Find the current crossing the square u I-0.25 111. |y|s0.25ni. 2=0. Am. (o) 27.9 A; (ft) 12.5 A6.49.A Im41ow. thin-wallcd. levtangular conductor 0.01 by 0.02 in carries a currentSchaum’s outline of theory and problems (6)
a. I ■>) v/m, 12.19 X to •*(•.+•,) C/m2. xiiox631.A conductor that extends into the region I <■ 0 has one face in the plane 2=0. over wlikti tlierc B ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 -ELECTROMAGNETICSCHAP. 1|VECTOR ANALYSISEXAMPLE 1 Given A = 2a, + 4a, - 3a, and •find A • B and A X B.A • B = (2XD + (4X-1) + (-3)10)- -2AXB-a, 21A 4 -Gọi ngay
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