Lecture mechanics of materials chapter six symmetric bending of beams
➤ Gửi thông báo lỗi ⚠️ Báo cáo tài liệu vi phạmNội dung chi tiết: Lecture mechanics of materials chapter six symmetric bending of beams
Lecture mechanics of materials chapter six symmetric bending of beams
M. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetr Lecture mechanics of materials chapter six symmetric bending of beams ric bending of beams, its limitations, and its applications foi a strength-based design and analysis.2.Visualize die direction of noimal and siieai stresses and die surfaces on which they act in die symmetric bending of beams.On April 29th. 200? at 3:45 AM. a tanker tiuck crashed into a pylon on int Lecture mechanics of materials chapter six symmetric bending of beams erstate so near Oakland. California, spilling 8600 gallons of fuel that Ignited. Fortunately no one died But the heat generated from the Ignited fuel,Lecture mechanics of materials chapter six symmetric bending of beams
severely reduced the strength and Stiffness of the steel beams of the interchange, causing it to collapse under its own weight (Figure 6.1fl). In thiM. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetr Lecture mechanics of materials chapter six symmetric bending of beams member can be called a beam? Figurc 6.1 b shows a bookshelf whose length 15 much greater than Its width or thickness, and the weight of the books is perpendicular to its length. Girders, the long horizontal members in bridges and highways transmit the weight of the pavement and traffic to the column Lecture mechanics of materials chapter six symmetric bending of beams s anchored to the ground, and again the weight is perpendicular to the member. Bookshelves and girders can be modeled as beams—long structural memberLecture mechanics of materials chapter six symmetric bending of beams
on which loads act perpendicular to the longitudinal axis The mast of a ship, the pole of a sign post, the frame of a car. the bulkheads m an aircraftM. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetr Lecture mechanics of materials chapter six symmetric bending of beams lowing the logic described m Figure 3.15. but subject to the limitations described in Section 3.13.Figure 6.1 (a) 1-80 interchange collapse, (b) Beam example.Pnrtoi frail lil^i AV IT* * 11« ■iliictba fin -jMaKcAtbiiiMn6.1 PRELUDE TO THEORYAs a prelude to theory', we consider several examples, all so Lecture mechanics of materials chapter six symmetric bending of beams lved using the logic discussed m Section 3.2. They highlight observations and conclusions that will be formalized in Section 6.2.•Example 6 1. discretLecture mechanics of materials chapter six symmetric bending of beams
e bars welded to a rigid plate, illustrates how to calculate the bending nonnal strains from geometry.•Example 6.2 shows the similarity of Example 6.1M. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetr Lecture mechanics of materials chapter six symmetric bending of beams s how the choice of a material model alters the calculation of the internal bending moment. As we saw in Chapter 5 for shafts, the material model affects only the stress distribution, leaving all other equations unaffected Thus, the kinematic equation describing strain distribution is not affected N Lecture mechanics of materials chapter six symmetric bending of beams either arc the static equivalency equationsAuimi 2012M. CableMechanics of Materials: Symmetric Bending of BeamsMETHOD 2: PLANWe can use small-strain aLecture mechanics of materials chapter six symmetric bending of beams
pproximation and find the deformation component in the horizontal (original) direction for bars 1 and 3. The normal strains can then be found.SOLUTIONM. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetr Lecture mechanics of materials chapter six symmetric bending of beams . and F move to Bị. D._. and Fl shown. We can use point z>| to find the relative displacements of points B and F as shown in Equations (E4) and (E5). We make use of small strain approximation to the sine function by its argument;Auj - DF> - D.Ft - ZJjFjSmv - 2v - 0.1222 in.Aut = B.D = DjD. = B1D1sin Lecture mechanics of materials chapter six symmetric bending of beams v *2v = 0.1222 in.Figure 6.4 Alternate method for normal strain calculations in Example 6.1.The normal strains in the bars can be found asAu. -0.1222Lecture mechanics of materials chapter six symmetric bending of beams
in. . _____________________ -Au, 0.1222 m.51 = ,„11 = ~",: = -0.004073 in.'in. S) =‘;30 in. 30 in.30 in. 30 in.(E4)(E5)= 0.004073 in.'in.(E6)ANS. Cj -M. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetrM. \ ableMechanics of Materials: Symmetric Bending of BeamsCHAPTER SIXSYMMETRIC BENDING OF BEAMSLearning objectives1.Understand the tlieory of symmetrGọi ngay
Chat zalo
Facebook