ISM chapter27 kho tài liệu bách khoa
➤ Gửi thông báo lỗi ⚠️ Báo cáo tài liệu vi phạmNội dung chi tiết: ISM chapter27 kho tài liệu bách khoa
ISM chapter27 kho tài liệu bách khoa
27Current and ResistanceCHAPTER OUTLINE27.1Electric Current27.2Resistance27.3A Model for Electrical Conduction27.4Resistance and Temperature27.5Superc ISM chapter27 kho tài liệu bách khoaconductors27.6Electrical PowerI An asterisk indicates a question or problem new to this edition.ANSWERS TO OBJECTIVE QUESTIONSOQ27.1Answer (d). One ampere-hour is (1 c/s)(3 600 s) = 3 600 coulombs.OQ27.2The ampere-hour rating is the quantity of charge that the battery can lift though its nominal pot ISM chapter27 kho tài liệu bách khoaential difference. (i) Answer (e). We require pL/AA = 3pL/Ag. Then Aa /Ap = 1 /3.OQ27.3(ii) Answer (d). xrAfxr* = 1/3 gives r4/r8= 1/V3. The ranking iISM chapter27 kho tài liệu bách khoa
s c > a > b > d > e. BecauseOQ27.4(a)I = AV / R, so the current becomes 3 times larger. (b)p= I AV = I:R, so the current is y/3 times larger. (c)R is 27Current and ResistanceCHAPTER OUTLINE27.1Electric Current27.2Resistance27.3A Model for Electrical Conduction27.4Resistance and Temperature27.5Superc ISM chapter27 kho tài liệu bách khoaurrent has a small decrease. (i) Answer (a). The cross-sectional area decreases, so the currentdensity increases, thus the drift speed must increase. 200 C2014 Cc-ngjgc learning. All Rights. Rcvcnvd. May no< be scanned, copied or duplicated, or posted Io J publicly accessible webttte, in whole or in ISM chapter27 kho tài liệu bách khoa part.Chapter 27 201(ii) Answer (a). The cross-sectional area decreases, so the resistance per unit length, R/L = plA, increases.OQ27.5 Answer (c). /ISM chapter27 kho tài liệu bách khoa
= AV / R = 1.00 V /10.0 Q = 0.100 A = 0.100 c/s.Because current is constant, / = dq I dt = Sq I st, and we find thatAợ = 1st = (0.100 C/s)(20.0 s) = 227Current and ResistanceCHAPTER OUTLINE27.1Electric Current27.2Resistance27.3A Model for Electrical Conduction27.4Resistance and Temperature27.5Superc ISM chapter27 kho tài liệu bách khoanew cross-sectional area is three times the original.Originally, R “• Finally, Rf. ===aA r f 3A 9A 9OQ27.8 Answer (b). Using Ro = 10.0 Q at T = 20.0 °C, we haveR = RoU + oAT) ora = R/Rọ-l _10.6/10.0-1___= 8.57 X ỊQ-4 0(2'*AT (90.0°C-20.0°C)At T = -20.0°C, we haveR = R0(l + aAT)= (10.0 Q)[l + 8.57 xi ISM chapter27 kho tài liệu bách khoao-* °C*1 (-20.0 >C-20.0°C)] = 9.66 QOQ27.9 Answer (a). R = V// = 2 V/2 A = 1 Q.OQ27.10 Answer (c). Compare resistances:Kạ = :P^A(dx/2)2 LAdB2 (2LB) dFISM chapter27 kho tài liệu bách khoa
2 = 2 = 2Pp pLB/n(dB/2)~ dA Lp (2dg)4 227Current and ResistanceCHAPTER OUTLINE27.1Electric Current27.2Resistance27.3A Model for Electrical Conduction27.4Resistance and Temperature27.5Superc27Current and ResistanceCHAPTER OUTLINE27.1Electric Current27.2Resistance27.3A Model for Electrical Conduction27.4Resistance and Temperature27.5SupercGọi ngay
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