ISM chapter28 kho tài liệu bách khoa
➤ Gửi thông báo lỗi ⚠️ Báo cáo tài liệu vi phạmNội dung chi tiết: ISM chapter28 kho tài liệu bách khoa
ISM chapter28 kho tài liệu bách khoa
28Direct-Current CircuitsCHAPTER OUTLINE28.1Electromotive Force28.2Resistors in Series and Parallel28.3Kirchhoff's Rules28.4RC Circuits28.5Household W ISM chapter28 kho tài liệu bách khoaWiring andElectrical SafetyI* An asterisk indicates a question or problem new to this editionJNSWERS TO OBJECTIVE QUESTIONSOQ28.1 Answer (a). When the breaker trips to off, current does not go through the device.OQ28.2(i) Answer (d). The terminal potential difference is AV = £ - ỉr,where current Ỉ w ISM chapter28 kho tài liệu bách khoaithin the battery is considered positive when it flows from the negative to the positive terminal. When Ị = 0, AV = £ (ii) Answer (b). When the batterISM chapter28 kho tài liệu bách khoa
y is absorbing electrical energy, the current within the battery flows from the positive to the negative terminal; in this case, / is considered negat28Direct-Current CircuitsCHAPTER OUTLINE28.1Electromotive Force28.2Resistors in Series and Parallel28.3Kirchhoff's Rules28.4RC Circuits28.5Household W ISM chapter28 kho tài liệu bách khoaa resistor in this series connection is directly proportional to the resistance of that resistor, AV = /R, and independent of its location within the series connection.OQ28.4 Answer (b). because the appliances are connected in parallel, the total power used is proportion to the total current:y p ZP- ISM chapter28 kho tài liệu bách khoaZ/,AV = AVy/,.-.V/j = ^240 t>2014 Cengagc txuming. All Right* Rif*cr»vd. May not be scanned, copied or duplicated, or ported to a publicly accu-Mble wISM chapter28 kho tài liệu bách khoa
ebute. in whole or in part.Chapter 28 241orOQ28.5p + p +Py J _ * twalMr * toaster 1 * oven '■AV(1.30xl0’ + 1.00xl0’ + 1.54xl0’J w ■ t .Answer (b). Whe28Direct-Current CircuitsCHAPTER OUTLINE28.1Electromotive Force28.2Resistors in Series and Parallel28.3Kirchhoff's Rules28.4RC Circuits28.5Household W ISM chapter28 kho tài liệu bách khoa With the resistors connected in parallel, the potential difference across each resistor is AV and the power delivered to each resistor is P| = (AV)2/R. Thus, the total power delivered in this case isp =2P, = 2^p-=4 p 1RwOQ28.6OQ28.7OQ28.8OQ28.9OQ28.10OQ28.11OQ28.12= 4PS = 4(8.0 W) = 32 w2RAnswer (a ISM chapter28 kho tài liệu bách khoa), (d). According to the relationship for resistors in series,= £] + R2 +•■•28Direct-Current CircuitsCHAPTER OUTLINE28.1Electromotive Force28.2Resistors in Series and Parallel28.3Kirchhoff's Rules28.4RC Circuits28.5Household W28Direct-Current CircuitsCHAPTER OUTLINE28.1Electromotive Force28.2Resistors in Series and Parallel28.3Kirchhoff's Rules28.4RC Circuits28.5Household WGọi ngay
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