PART ONE solutions to exercises

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PART ONE solutions to exercises

Part OneSolutions to ExercisesChapter 2Review of Probability■ Solutions to ExercisesI.(a) Probability distribution function for yOutcome (number of he

PART ONE solutions to exercises eads)y-0r-1Y-2probability0.250.50.25(b) Cumulative probability distribution function for yOutcome (number of heads)y<002Probability00.250

.751(c)fiỴ-E(Y) = (Qx 0.25) + (1X 0.50) + (2 X 0.25) = 1.00Using Key Concept 2.3: var(i') = E(Y‘ I -(£(1')]'\ and E( y-) = (0-' X 0.25) + (12 X 0.50) PART ONE solutions to exercises

+ (2- X 0.25) = 1.50 so that vartK) = £

PART ONE solutions to exercises

0.30. Pr(.v = l)-0.70. So(a)ụ, - £(ĩ) - 0 X Pr (r - 0)+1X Pr (y -1) -0x0.22 I 1x0.78-0.78.//,. - £( A) - 0 X Pr (A' - 0)+1X Pr (A -1) -0x0.30 + 1x0.70

Part OneSolutions to ExercisesChapter 2Review of Probability■ Solutions to ExercisesI.(a) Probability distribution function for yOutcome (number of he

PART ONE solutions to exercises xPr(y = I)-(-O.78)2 X 0.22 + 0.22’ X 0.78 = 0.1716.4 Stcck.'Watson - Introduction to Econometrics - Second Edition(c)Table 2.2 shows Pr(A’ = 0,y = 0)

= 0.15, Pr(A'=o.y = 1) = 0.15, Pr(A' = 1, Y = 0) = 0.07, Pr(A'=l, y = 11 = 0.63. Socr n. = cov(A'. n = £[( X - n>:)(y - //}.)]= (0 - 0.70)10-0.78)Pr( PART ONE solutions to exercises

A = 0. Y = 0)+ (0 - 0.70X1 - 0.78) Pr (A' = 0, y = 1)+ (1 - 0.70X0 -0.78) Pr( A' = 1. y = 0)+ (1 - 0.70X1 -O.78)Pr(A' = 1. y = 1)= (-0.70) X (-0.78) X

PART ONE solutions to exercises

0.15 + (-0.70) X 0.22 X 0.15+ 0.30 X (-0.78) X 0.07 + 0.30 X 0.22 X 0.63= 0.084,cor(X,Y) =0.084

Part OneSolutions to ExercisesChapter 2Review of Probability■ Solutions to ExercisesI.(a) Probability distribution function for yOutcome (number of he