Instructors solution manuals to college physics
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Instructors solution manuals to college physics
Instructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical Univer Instructors solution manuals to college physics rsityPrepared byVahe Peroomlan & John GordonAustralia • Brazil • Japan • Koraa • Haxico • Singapore • Spain • United Kingdom • Unitod Stateswww.pdfgrip.com1 IntroductionANSWERS TO WARM-UP EXERCISES1.(a) The number given. 568 017. has SIX significant figures, which we will retain 111 converting the n Instructors solution manuals to college physics umber to scientific nota-tion. Moving the decimal five spaces to the left gives US the answer. b.68O 17 * 10'1-(b)The number given. 0 000 309. has thrInstructors solution manuals to college physics
ee significant figtues. which we will retain It) converting the number to scientific notation. Moving the decimal four spaces to the right gives US tiInstructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical Univer Instructors solution manuals to college physics r momentum.3.Examining the expression shows that the units of meters and seconds squared (r) appear in both the numerator and the denominator. and therefore cancel out. We combine the numbers and units separately, squaring the last tenn before doing so:( 1 no ™i Í 100 tan Ì ( 60.0s V X ' rJl. l.OOxl Instructors solution manuals to college physics O’m.H. 1.00mm)= (7.00)[-^ V1.00X10’,l.OOcubitus Ị I,.... .. I5 The area of the house in squate feet (1 420 fFi contains 3 significant figures. Our ansInstructors solution manuals to college physics
wer will therefore also contain three significant figures Also note that the conversion fiom feet to meters is squared to account for the ft’ units inInstructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical Univer Instructors solution manuals to college physics 6 783 m'jriiis answer must be rounded to contain the same number of significant figures as the least accurate factor in the product Tire least accurate factor is the length, which contains 2 significant figures. since the trailing zero is not significant (see Section 1.6). The correct answer for the Instructors solution manuals to college physics area of the airsuip IS [6.80 ~Adduig the three numbers with a calculator gives 21.4 + 15 - 17.17 + 4.003 = 57.573. However, this answer must be roundInstructors solution manuals to college physics
ed to contam the same number of significant fii significant figures The collect answer is therefore |5ias the least accurate number m the stun, which Instructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical Univer Instructors solution manuals to college physics so we will express our answer in three significant figures Tire specified point. (-5.00.12.00). is in the second quadrant since V < 0 andy > 0. To find the polar coordinates (r. 0) of this point, we User = -jx: + r = V(5 00):+(12.00): =13.0 and1WWW pdfgrip.come= = tail - j j = -67.3°Since the point Instructors solution manuals to college physics IS Hl the second quadrant, we add 180° to tins angle to obtain Ớ = -67.3® +1 SO1' = 113®. The polar coordinates of the point are therefore |(13 0.19.Instructors solution manuals to college physics
Refer to .ANS. FIG 9. The height of the tiee is described by the tangent of the 26® angle, orInstructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical UniverInstructor Solutions ManualCollege PhysicsTENTH EDITIONRAYMOND A. SERWAYEmeritus. James Madison UniversityCHRIS VUILLEEmbry-Riddle Aeronautical UniverGọi ngay
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