Physics 10e sol jearl walker david halliday

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Physics 10e sol jearl walker david halliday

INSTRUCTO cni iiTiniJCFUNDAMENTALS OF10th editionJEARLWALKEREXTENDEDWileyCHAPTER ỉ(a)Since 1 km = 1 X 103 m and 1 m = 1 X 106 /an.1km = 10'm = (10? m)

Physics 10e sol jearl walker david halliday )(106 //m/m) = IO9 //m.The given measurement is 1.0 km (two significant figures). which implies our result should be written as 1.0 X 109 /an.(b)We ca

lculate the number of microns in 1 centimeter. Since 1 cm = 10“* 111.1cm = 10“2m = (10“2m)(10ỗ//m/m) = 104 //mWe conclude that the fraction of one cen Physics 10e sol jearl walker david halliday

timeter equal to 1 0 /an is 1.0 X 10“*.(c)Since 1 yd = (3 ft)(0.3048 m ft) = 0.9144 in.1.0yd = (0.91m)(106//m/m) = 9.1 X 10' //m.4. (a) Using the conv

Physics 10e sol jearl walker david halliday

ersion factors 1 inch = 2.54 cm exactly and 6 picas = 1 meh. we obtainA OA______ZA OA „ J 1 inch ji 6 picas .0.80 cm = (0.80 cm) - ' -—.* 1.9 picas.v

INSTRUCTO cni iiTiniJCFUNDAMENTALS OF10th editionJEARLWALKEREXTENDEDWileyCHAPTER ỉ(a)Since 1 km = 1 X 103 m and 1 m = 1 X 106 /an.1km = 10'm = (10? m)

Physics 10e sol jearl walker david halliday 2.54 cm1 inch 1 pica /5. THINK This problem deals with conversion of fill longs to rods and chains, all of which are units for distance.EXPRESS Given

that 1 furlong = 201.168 m. 1 rod = 5.0292 m and 1 chain = 20.117 m, the relevant conversion factors are1.0 furlong = 201.168 m = (201.168 ịtí)= 40 r Physics 10e sol jearl walker david halliday

ods.*5.0292 ịríand1.0 furlong = 201.168 111 = (201.168 X) 1™“” = 10 chains.20.117/nNote the cancellation of m (meters), the unwanted unit.ANALYZE Usin

Physics 10e sol jearl walker david halliday

g the above conversion factors, we find(a)the distance d in rods to be d = 4 .0 fill longs =(4.0 furlongs)1O{*S = 160 rods.1 fiirlongwww.pdfgrip.oom3

INSTRUCTO cni iiTiniJCFUNDAMENTALS OF10th editionJEARLWALKEREXTENDEDWileyCHAPTER ỉ(a)Since 1 km = 1 X 103 m and 1 m = 1 X 106 /an.1km = 10'm = (10? m)